0=0.02x^2+12x-11

Solution for 0=0.02x^2+12x-11 equation:

0=0.02x^2+12x-11

We move all terms to the left:

0-(0.02x^2+12x-11)=0

We add all the numbers together, and all the variables

-(0.02x^2+12x-11)=0

We get rid of parentheses

-0.02x^2-12x+11=0

a = -0.02; b = -12; c = +11;
Δ = b2-4ac
Δ = -122-4·(-0.02)·11
Δ = 144.88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-\sqrt{144.88}}{2*-0.02}=\frac{12-\sqrt{144.88}}{-0.04}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+\sqrt{144.88}}{2*-0.02}=\frac{12+\sqrt{144.88}}{-0.04}
$